2. In a barnyard, there is an assortment of chickens and cows. Counting heads, one gets 80; counting legs, one gets 184. How many of each are there? Note: To receive credit for this problem you need to define the variables, write a system of equations and solve the system to answer the question.
Accepted Solution
A:
Answer:68 chickens and 12 cows.Step-by-step explanation:Let x represents the number of chicken and y represents the number of cows in the barnyard,Given,Total heads = 80⇒ x + y = 80 ------(1),Also, total legs = 184,Since, a chicken has two legs and cow has 4 legs,⇒ 2x + 4y = 184 -----(2),Equation (2) - 2 × equation (1),We get,4y - 2y = 184 - 1602y = 24y = 12From equation (1),x + 12 = 80 ⇒ x = 80 - 12 = 68Hence, the number of chicken = 68,And, the number of cows = 12